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Patterns In Action Model() lambdaI'm walking through Patterns In Action and the Model constructor has:
SafeProxy.DoAction<ActionServiceClient>(Service, client => { response = client.GetToken(request); }); I looked up statement lambdas but am still confused how the above code works. Can someone help explain? M S, Mar 22, 2010
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Reply 1Usually, I wouldn't reply to a question asked months ago. However, other people might stumble across this one and also wonder how this works (even tough this code is obsolete, Pattern Framework 4.0 has a slightly different approach). ;) To understand how Lambda Expressions work, please read this article here: And now... well,... I was about explaining how this code works and noticed that I don't understand it either. Lamdas tend to be not that intuitive to understand. Service is a property that exposes a private field of type ActionServiceClient, while response is a local variable of type TokenResponse. request is a local instance of TokenRequest and initialized before the above call. The static DoAction method has the following header: It does call action(client) You need to know that the Lambda Expression here ressembles an anonymous method implementing an Action Delegate (Encapsulates a method that has no parameters and does not return a value). So in this case it is actually a typed action (hence the generic <T> which has a constraint that ensures that it implements the ICommunicationObject interface. Alright... putting it all together: This happens from within the SafeProxy class that is supposed to be able to execute even long running actions (since the communication takes place over some sort of network using most probably WCF as a communication channel). The response is stored in the response object. Hm... in the end I was somewhat able to explain a little bit... To learn more about action delegates, please read the article here: And more than that: Go and get Pattern Framework 4.0. -Chris Christian Jacob, Aug 17, 2010
@Zac Bai , @Hans Overkamp solution is a simple but useful one. An very simple improvement to it is to use for the second dictionary where the VALUE UserObject is actually a pointer to the UserObject in the dictionary. This would increase lookup\read performance by a factor of X or the amount of items in the hash table or dictionary. :)
Jan 26, 2012
Great answer and spot on! Exactly what I was looking for.
Mar 19, 2010
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